create a stellar application without installing stellar core in local system

Question

I want to create a stellar application which will have these functionality

Based on that i have generated keys:

var pair = StellarSdk.Keypair.random();
pair.secret();
pair.publicKey();

And to create account i hit this url in browser

How can i create a account in livenet without installing stellar-core

I did't find any livenet endpoint in stellar docs

Johan Stén · Accepted Answer · 2018-08-11 14:42:12Z

4

To create accounts you create a transaction containing a createAccount operation.

Friendbot is only there to give you an initial sum of testnet XLMs. Nothing else.

answered Aug 11 '18 at 14:42

Johan Stén

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I have used this code to create account :` StellarSdk.Keypair.random(); pair.secret(); pair.publicKey();` . If i make transaction without hitting https://friendbot.stellar.org?addr=XXXXXXXXXXXXXXXXXX url gives a 404 and Resource Missing exception – Ajit Soman Aug 11 '18 at 14:51
Keypair.random() only generates a keypair for you. To be able to use the account, it has to be registered on the ledger, and that's what the createAccount operation does. – Johan Stén Aug 11 '18 at 14:54
stellar.org/developers/js-stellar-base/reference/… – Johan Stén Aug 11 '18 at 15:00
That's right. An account can't exist without a minimum balance. And you can't create that minimum balance out of thin air, someone has to give it to you by way of a CreateAccount operation. – Synesso♦ Aug 12 '18 at 7:26

add a comment |

cesarm · Accepted Answer · 2018-08-11 14:43:07Z

You don't need to directly access Stellar Core, if you just want the above functionalities.

Use the livenet Horizon endpoint would be sufficient:

https://horizon.stellar.org/

For pre-built UI version, use the Laboratory: https://www.stellar.org/laboratory/

NOTE: StellarSdk.Network.useTestNetwork(); is for TESTNET, so you need to change it to something like StellarSdk.Network.usePublicNetwork();

p.s. I'd recommend trying first with testnet and observe if your calls match with the expected behaviour first.

2 Answers 2